A stone is thrown upwards from a tower with a velocity 50 ms –1 . Another stone is simultaneously thrown downwards from the same location with a velocity 50 ms –1 . When the first stone is at the highest point, the relative velocity of the second stone w.r.t. the first stone is (assume that second stone has not yet reached the ground):
Text Solution
Verified by ExpertsThe correct answer is:
C
v 1 = 50 – gT
v 2 = – 50 – gT
v r = v 1 – v 2 = 100 m/sec
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